CERTIFIED ETHICAL HACKER EXAM (CEHV13) TRAINING PDF MATERIAL & 312-50V13 RELIABLE PRACTICE QUESTIONS & CERTIFIED ETHICAL HACKER EXAM (CEHV13) EXAM PREP PRACTICE

Certified Ethical Hacker Exam (CEHv13) Training Pdf Material & 312-50v13 Reliable Practice Questions & Certified Ethical Hacker Exam (CEHv13) Exam Prep Practice

Certified Ethical Hacker Exam (CEHv13) Training Pdf Material & 312-50v13 Reliable Practice Questions & Certified Ethical Hacker Exam (CEHv13) Exam Prep Practice

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ECCouncil Certified Ethical Hacker Exam (CEHv13) Sample Questions (Q46-Q51):

NEW QUESTION # 46
You are the lead cybersecurity analyst at a multinational corporation that uses a hybrid encryption system to secure inter-departmental communications. The system uses RSA encryption for key exchange and AES for data encryption, taking advantage of the strengths of both asymmetric and symmetric encryption. Each RSA key pair has a size of 'n' bits, with larger keys providing more security at the cost of slower performance. The time complexity of generating an RSA key pair is O(n*2), and AES encryption has a time complexity of O(n).
An attacker has developed a quantum algorithm with time complexity O((log n)*2) to crack RSA encryption.
Given *n=4000' and variable 'AES key size', which scenario is likely to provide the best balance of security and performance?

  • A. AES key size=128 bits: This configuration provides less security than option A, but RSA key generation and AES encryption will be faster.
  • B. AES key size=256 bits: This configuration provides a high level of security, but RSA key generation may be slow.
  • C. AES key size=192 bits: This configuration is a balance between options A and B, providing moderate security and performance.
  • D. AES key size=512 bits: This configuration provides the highest level of security but at a significant performance cost due to the large AES key size.

Answer: A

Explanation:
A hybrid encryption system is a system that combines the advantages of both asymmetric and symmetric encryption algorithms. Asymmetric encryption, such as RSA, uses a pair of keys: a public key and a private key, which are mathematically related but not identical. Asymmetric encryption can provide key exchange, authentication, and non-repudiation, but it is slower and less efficient than symmetric encryption. Symmetric encryption, such as AES, uses a single key to encrypt and decrypt data. Symmetric encryption is faster and more efficient than asymmetric encryption, but it requires a secure way to share the key.
In a hybrid encryption system, RSA encryption is used for key exchange, and AES encryption is used for data encryption. This way, the system can benefit from the security of RSA and the speed of AES. However, the system also depends on the key sizes of both algorithms, which affect the security and performance of the system.
The key size of RSA encryption determines the number of bits in the public and private keys. The larger the key size, the more secure the encryption, but also the slower the key generation and encryption/decryption processes. The time complexity of generating an RSA key pair is O(n*2), where n is the key size in bits. This means that the time required to generate an RSA key pair increases quadratically with the key size. For example, if it takes 1 second to generate a 1024-bit RSA key pair, it will take 4 seconds to generate a 2048-bit RSA key pair, and 16 seconds to generate a 4096-bit RSA key pair.
The key size of AES encryption determines the number of bits in the symmetric key. The larger the key size, the more secure the encryption, but also the more rounds of encryption/decryption are needed. The time complexity of AES encryption is O(n), where n is the key size in bits. This means that the time required to encrypt/decrypt data increases linearly with the key size. For example, if it takes 1 second to encrypt/decrypt data with a 128-bit AES key, it will take 2 seconds to encrypt/decrypt data with a 256-bit AES key, and 4 seconds to encrypt/decrypt data with a 512-bit AES key.
An attacker has developed a quantum algorithm with time complexity O((log n)*2) to crack RSA encryption.
This means that the time required to break RSA encryption decreases exponentially with the key size. For example, if it takes 1 second to break a 1024-bit RSA encryption, it will take 0.25 seconds to break a 2048-bit RSA encryption, and 0.0625 seconds to break a 4096-bit RSA encryption. This makes RSA encryption vulnerable to quantum attacks, unless the key size is very large.
Given n=4000 and variable AES key size, the scenario that is likely to provide the best balance of security and performance is C. AES key size=192 bits. This configuration is a compromise between options A and B, providing moderate security and performance. Option A, AES key size=128 bits, provides less security than option C, but RSA key generation and AES encryption will be faster. Option B, AES key size=256 bits, provides more security than option C, but RSA key generation may be slow. Option D, AES key size=512 bits, provides the highest level of security, but at a significant performance cost due to the large AES key size.
References:
* Hybrid cryptosystem - Wikipedia
* RSA (cryptosystem) - Wikipedia
* Advanced Encryption Standard - Wikipedia
* Quantum computing and cryptography - Wikipedia


NEW QUESTION # 47
You are attempting to run an Nmap port scan on a web server. Which of the following commands would result in a scan of common ports with the least amount of noise In order to evade IDS?

  • A. nmap -sT-O- To
  • B. nmap-A-host-time 99-T1
  • C. nmap -sP- -p-65535-T5
  • D. nmap -A -Pn

Answer: A

Explanation:
-A: Perform an aggressive scan which select most of the commonly used options within nmap
-Pn: Means Don't ping
-p:scan specific ports
-sT: TCP Connect scan
-O: Operating system detection
-T0: timing template (extremely slow- evade FW)0


NEW QUESTION # 48
Which of the following is a component of a risk assessment?

  • A. DMZ
  • B. Physical security
  • C. Administrative safeguards
  • D. Logical interface

Answer: C


NEW QUESTION # 49
Bill has been hired as a penetration tester and cyber security auditor for a major credit card company. Which information security standard is most applicable to his role?

  • A. PCI-DSS
  • B. FISMA
  • C. Sarbanes-OxleyAct
  • D. HITECH

Answer: A


NEW QUESTION # 50
"........is an attack type for a rogue Wi-Fi access point that appears to be a legitimate one offered on the premises, but actually has been set up to eavesdrop on wireless communications. It is the wireless version of the phishing scam. An attacker fools wireless users into connecting a laptop or mobile phone to a tainted hot- spot by posing as a legitimate provider. This type of attack may be used to steal the passwords of unsuspecting users by either snooping the communication link or by phishing, which involves setting up a fraudulent web site and luring people there." Fill in the blank with appropriate choice.

  • A. Collision Attack
  • B. Sinkhole Attack
  • C. Signal Jamming Attack
  • D. Evil Twin Attack

Answer: D

Explanation:
https://en.wikipedia.org/wiki/Evil_twin_(wireless_networks)
An evil twin attack is a hack attack in which a hacker sets up a fake Wi-Fi network that looks like a legitimate access point to steal victims' sensitive details. Most often, the victims of such attacks are ordinary people like you and me.
The attack can be performed as a man-in-the-middle (MITM) attack. The fake Wi-Fi access point is used to eavesdrop on users and steal their login credentials or other sensitive information. Because the hacker owns the equipment being used, the victim will have no idea that the hacker might be intercepting things like bank transactions.
An evil twin access point can also be used in a phishing scam. In this type of attack, victims will connect to the evil twin and will be lured to a phishing site. It will prompt them to enter their sensitive data, such as their login details. These, of course, will be sent straight to the hacker. Once the hacker gets them, they might simply disconnect the victim and show that the server is temporarily unavailable.
ADDITION: It may not seem obvious what happened. The problem is in the question statement. The attackers were not Alice and John, who were able to connect to the network without a password, but on the contrary, they were attacked and forced to connect to a fake network, and not to the real network belonging to Jane.


NEW QUESTION # 51
......

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